For a certain breed of cat, short tails are dominant (7) and long tails are recessive (). The Punnett square below shows a cross between two parents.
What is the phenotype ratio for this cross?
T
t
Tt
tt
t
Tt
tt
A. 1 long, 3 short
ОО
O B. 4 long, 0 short
O C. 3 long, 1 short
O D. 2 long, 2 short

i would think it's dendrites

we solve the problem using the hardy-wineberg equation.

let us start with the homozygous recessive proportion of individuals with sickle cell anaemia,

we have the proportion as q² = 0.25.

∴ q = 0.5 (frequency of hbs in population)

further,

solving for the frequency of normal cell by using the fact that,

p + q = 1

∴ p = 1 - 0.5 = 1 - 0.5 = 0.5

now we can calculate 2pq in p² + 2pq + q², which is the frequency for heterozygous carriers of sickle cell anaemia,

∴ 2pq = 2 x 0.5 x 0.5 = 0.5

and the homozygous normal cell individuals proportion is given by the expression,

∴ p² = 0.5² = 0.25

hence, the carriers for sickle cell anaemia are in proportion, 0.5, or 50%.