Crossing true breeding dark-coated sheep with true breeding light-coated sheep always results in 100% dark-coated offspring. You are screening a population of Soay sheep for coat color, and you count 368 dark sheep and 132 light sheep. Assuming that this population is in Hardy-Weinberg equilibrium, what is the genotype frequency (not allele frequency) of the homozygous recessive sheep for TYRP1 gene

The correct answer is : 0.264

Explanation:

The total population of the Soay sheep is : 368 dark sheep + 132 light sheep

          = 500 sheep.

Total dark coat sheep ( dark allele represented by D as it is dominant) = 368

Total light coat sheep ( light allele represented by d as it is recessive) = 132

As we know crossing is took place in between true breeding:

           DD × dd

F1,           Dd        ( all are dark coat)

So, the genotype frequency of the homozygous recessive allele is

       = 132/500               (by Hardy - Weinberg equation)

       = 0.264

Thus, the correct answer is 0.264.

the reason the two sea urchins don't compete with each other for food, resources, etc. is because the urchins have adapted to the environment but they have also adapted to each other. this is most likely because the genes of the sea urchins.