Sex-linked traits punnet squares - please help walk me through it! I’m so confused haha

Explanation:

a) The allele for hemophilia is Xh and that for normal is XH.

Crossing a hemophiliac male, Xh Y, with a normal female XH XH,

b) Both parents are normal and children still having hemophilia means that the mother is a carrier.

Let's see how it'll work out if we cross a normal male with a carrier female,

XH Y × XH Xh

This means that the possibility of a female being normal, a carrier or not, is 100%. The possibility of a male being normal is 50% and the possibility of him being a hemophiliac is also 50%.

Thus it's possible that all 7 sons get hemophilia as each male baby has a 50% chance of having the genotype Xh Y. And it makes sense that all the females are normal. Those females could have the genotypes XH XH, or XH Xh (carriers).

c. is the correct answer