In humans, having freckles is dominant over not having freckles. A heterozygous male with freckles has children with a female who does not have freckles. What fraction/percent of the children will not have freckles?

50%

Explanation:

If you do out the punnet square Ffxff, the result will be 50% of offspring with heterozygous (dominant trait is shown) and 50% will be homozygous recessive

segmentation=endoskeleton=backbone=coelom=tissues

due to the fact that it skipped a generation we can tell it is definitely not a dominant trait, therefore it must be recessive. i think this is right let me know!

explanation: