Round seeds and yellow seed color are dominant to wrinkled seeds and green seed color. What is the probability of having offspring that have wrinkled seeds and yellow seed color for the cross RRYY ´ RrYy? 0 percent 25 percent 50 percent 100 percent

0%

Explanation:

This question involves two distinct genes; one coding for seed shape and the other for seed colour. The allele for you seeds (R) is dominant over the allele for wrinkled seeds (r) in the first gene while the allele for yellow seeds (Y) is dominant over allele for green seeds (y).

In a cross involving RRYY (homozygous dominant for both traits) and RrYy (heterozygous for both genes), the following allelic combinations of gametes will be produced:

RRYY- RY, RY, RY, RY

RrYy- RY, Ry, rY, ry

Using these gametes in a punnet square (see attached image), 16 possible offsprings will be produced. The genotypes of the offsprings in the ratio 1:1:1:1 will be:

RRYY (4)

RRYy (4)

RrYY (4)

RrYy (4)

According to the question, offspring that have wrinkled seeds and yellow seed color will have genotype: rrYY or rrYy.

This genotype is not one of those that will be produced by the cross between a RRYY and RrYy parent. Hence, the probability of having an offspring with wrinkled seeds and yellow seed color is 0%

try using substitution:

x + y - 6 = x - y. (i'm not giving you the exact answer). since 0 = x - y, then sub 0 in the equation with x - y. combine your like terms, and then use inverse operations, and you'll have your answer.

: -)