A homozygous recessive parent for no freckles's and heterozygous parent for freckles have a what is the of a these parent is having a child with no freckless

50% chance or 1/2.

Explanation:

Let's denote the no freckles allele with f and the freckles allele with F since it is dominant over the no freckles trait.

One parent is homozygous recessive: ff

The other parent is heterozygous (So they have freckles): Ff

Let's do a Punnett Square to calculate the possibility of the offspring having freckles or not. (The Punnett Square may not be perfect)

  |   F      f

f  | Ff     ff

f  | Ff     ff

Two of the offspring have Ff, meaning they will have freckles, and two of the offspring have ff, meaning they will not have freckles.

2 out of 4 don't have freckles, which means a 50% chance or 1/2.

the answer is true when observing or determining population size, a direct observation is use, in which each organism is counted in a population or in an area. one benefit of this measure is that you get the exact population count but it will take a long time to  determine  the  size  of a  population.