What is the volume of 0.25 mol of ammonia gas at 1.00 atm and 273 K? (R= 0.0821 Latm/molK)What is the volume of 0.25 mol of ammonia gas at 1.00 atm and 273 K? (R= 0.0821 Latm/molK)

5.6L

Explanation:

Given parameters:

number of moles  = 0.25mol

pressure on gas  = 1atm

temperature  = 273K

Gas constant R = 0.0821Latm/molK

Unknown:

Volume of gas  = ?

Solution:

Using the ideal gas equation, we can solve this problem. The equation is a combination of the three gas laws: Boyle's law, Charles's law and Avogadro's law.

It is mathematically expressed as;

             PV = nRT

where P is the pressure

           V is the volume

          R is the gas constant

          T is the temperature

          n is the number of moles

All the parameters are in the appropriate units and we simply solve for the volume of the gas;

                1 x V = 0.25 x 0.0821 x 273

                      V  = 5.6L

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