In humans, the gene for curly hair (H) is incompletely dominant to the gene for straight hair (h). Individuals that are heterozygous (Hh) have wavy hair. Two wavy-haired heterozygous parents have a child. What is the likeliness that the child will have wavy hair?

The likeliness that the child that the two wavy-haired heterozygous parents will have will possess wavy hair is: 50%

Given the following:

Two parents that are heterozygous are: (Hh) x (Hh)

The cross between both parents will produce the following offspring as shown in the Punnett Square attached below:

Therefore, the likeliness that the child that the two wavy-haired heterozygous parents will have will possess wavy hair is: 50%

Learn more here:

link

1/2 (50%) of the offspring will have wavy-hair

Explanation:

The question is describing a autosomal type of inheritance pattern, being the dominant trait curly hair (allele H), and the recessive (non-dominant) trait straight hair (allele h). There are three phenotypes one can obtain from this allele: HH ⇒ Curly hair, Hh ⇒ Wavy hair, and hh ⇒straight hair. We are informed that two wavy-haired heterozygous parents have a child, meaning that both parents present a genotype of Hh. To obtain the probability of type of offspring, it is necessary to perform a Punnet square:

             H      |      h

———————————

H    |     HH     |    Hh      

———————————

h    |     Hh       |   hh    

One can conclude that the amount of offspring with wavy-hair phenotype, will be 2/4 = 1/2 = 50%

answer: land bridge theory. land bridge theory held that shifting portions of dry land explained the finding of identical species on different continents. plate tectonic theory eventually eliminated the land bridge theory.