In the Hardy-Weinberg equation shown below, p is the frequency of the dominat allele, and q is the recessive allele

p² + 2pq + q² = 1

What does 2pq represent in this equation

A) The frequency of the homozygous recessive genotype

B) The frequency of all the genotypes

C) The frequency of the homozygous dominant genotype

D) The frequency of the heterozygous genotype

Option D- frequency of the heterozygous qenotype

Explanation:

In the Hardy-Weinberg equilibrium , 2pq stands for the genotype frequency of heterozygotes (Aa) in a population at the state of equilibrium. dominant homozygotes (AA) is represented by the p-square and q- square represents the recessive homozygotes (aa) frequency. p represents the allele frequency of A Allele and q stands for the allele frequency of the allele a. Summation of the terms gives an equal to 1(100%). The sum of all of these terms is always equal to due to the fact that the 3 frequencies in the equation are the available or possible allele combinations.

Hardy-Weinberg is relevant for it helps us in comparison of a population's actual genetic structure as time goes on along with the genetic structure we are to get if really population was in Hardy-Weinberg equilibrium state that is population was not evolving.

c

explanation:

i believe your answer would be c.. : )