A rooster with gray feathers is mated with a hen of the same phenotype. Among their offspring, 15 chicks are gray, 6 are black, and 8 are white. What is the simplest explanation for the inheritance of these colors in chickens? What offspring would you predict from the mating of a gray rooster and a black hen?

Alleles for feather colour exhibit incomplete dominance or co-dominance.

50% gray offspring + 50% black offspring

Explanation:

It means that the alleles for feather colour in the hen exhibit incomplete dominance or co-dominance over one another.

Assuming the allele for white colour is B, white colour will be b while the heterozygote Bb gives the gray phenotype.

Gray rooster + gray hen = 15 gray chicks, 6 black chicks and 8 white chicks.

15:6:8 is roughly 2:1:1 which is phenotypic ratio obtainable from crossing two heterozygous individuals as pointed out by Mendel.

Bb   x   Bb = 1BB, 2Bb, and 1bb

Crossing the gray rooster (Bb) with a black hen (bb):

Bb   x   bb = Bb, Bb, bb, and bb

          = 2Bb (gray):2bb (black)

50% of the offspring will be gray while the remaining 50% will be black.

silty loam

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one part of the electromagnetic spectrum that arrives on earth as solar radiation from the sun is the visible spectrum. wavelengths of the visible spectrum combine to form what we refer to as

answer - d) ultraviolet radiation.

violet /   380–450 nm / 668–789 thz

violet is number 1 in the chart of visible light.