Genes A and B are located 10cM from each other on a chromosome. Gene C is located 25cM from gene A and 15cM from gene B. What is the probability that the trihybrid ABC/abc will produce any kind of recombinant gamete

0.235

Explanation:

Given

Distance between A and B = 0.10

Distance between B and C = 0.15

Distance between A and C = 0.25

The probability of double crossovers (DCO) are determined by the product of two single crossovers;

Therefore, the probability of a DCO = 0.10 * 0.15

= 0.015

= 1.5%

As the failure to detect a recombination is in DCO, the loci at 25cM will only show recombination at a frequency of:

25 - 1.5

= 23.5%

Hence, the probability that the trihybrid ABC/abc will produce any kind of recombinant gamete = 23.5% = 0.235

bru what tyep of qus is dis

this is more of a statement than a question. is there answers to go along with this, or is it opinion based?