A man heterozygous for long eyelashes marries a woman with short eyelashes. Draw a punnett square to determine the possible genotypes of their children. What is the likelihood of their child having short eyelashes?

See the attached for the Punnet square

Likelihood of their child having short eye lashes - 50% or 1/2

Explanation:

Let the allele for eye lashes be represented by E. Homozygous genotype will be EE (for long eye lashes) or ee (for short eye lashes) while heterozygous genotype will be Ee. Assuming long eye lashes allele E is dominant over shor short eye lashes e:

Heterozygous man marries a short eye lashes woman: Ee   x   ee

Ee  x  ee = Ee (long lashes), Ee (long lashes), ee (short lashes) and ee (short lashes.

That is, 50% or 1/2 of the offspring will have long eye lashes while the remaining 50% or 1/2 will have short eye lashes.

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