The frequency of carriers for a rare autosomal recessive genetic condition is 0.04 in a population. Assuming this population is in Hardy-Weinberg equilibrium, what is the allele frequency of the recessive allele?

a. 0.2
b. 0.4
c. 0.64
d. 0.8
e. Not enough information is provided.

The right answer is option A

Explanation:

Hardy-Weinberg equilibrium states that the variations in genetic distribution will always be constant as long as there are no external factors to disturb it across generations like mutations, genetic drift and gene flow among others. This principle is an ideal situation and is not really applicable in reality.

A simple formula for the Hardy-Weinberg principle is

+ 2pq + = 1 and p + q = 1 where p is the frequency of the dominant allele and q is the frequency of the recessive allele. While and  are the frequencies of the dominant and recessive genes respectively.

The frequency of a recessive genetic condition of 0.04 in a population means 4% of the population has a recessive genetic condition.

= 0.04 Genetic condition

q = square root of 0.04 = 0.2 Since q is the frequency of the allele then the frequency is 20%

a

explanation:

many plants naturally reproduce this way, but it can also be induced artificially. horticulturalists have developed asexual propagation techniques that use vegetative plant parts to replicate plants. success rates and difficulty of propagation vary greatly. monocotyledons typically lack a vascular cambium and therefore are harder to propagate.

the answer to your question is tooth decay.