In mice, an allele for apricot eyes (a) is recessive to an allele for brown eyes (a ). At an independently assorting locus, an allele for tan (t) coat color is recessive to an allele for black (t ) coat color. A mouse that is homozygous for brown eyes and black coat color is crossed with a mouse having apricot eyes and a tan coat. The resulting F1 are intercrossed to produce the F2.

The answer is 1/16.

Explanation:

The question is incomplete, here is the complete question:

In mice, apricot eyes (a) is recessive to an allele for brown eyes(A). At an independently assorting locus, the allele for tan coat color (t) is recessive to black coat color (T). A homozygous brown eyed, black coated mouse is crossed with a mouse having apricot eyes and a tan coat. The resulting F1 are intercrossed to produce the F2. At what frequency would you expect a mouse with apricot eyes and tan coats?

The first two genotypes crossed to produce F1 are brown eyed/black coat and apricot eye/tan coat and their genotypes should be AATT and aatt respectively.

Then there is only one possible genotype for F1 which is AaTt.

Intercrossing the resulting F1 which is AaTt x AaTt will result in F2 which looks like;

AT           At            aT            at

ATAATTAATt  AaTT   AaTt

AtAATtAAtt  AaTt   Aatt

aTAaTTAaTtaaTT   aaTt

atAaTtAatt         aaTt           aatt

The question asked is the frequency of observing apricot eyes and tan coat in the F2 generation, which means that the genotype should be "aatt" and that is only 1/16 as it can be seen from the crossing results above.

I hope this answer helps.

chordata is the answer

fabric is silk wool ext. paper isnt

explanation:

u cant make fabric out of paper cause paper comes from wood while fabric comes from animals