A frog population is living in the lake near the campus. After a field survey, scientists reported that there are estimated 650 frogs in the lake area (which is 130 squared meter in size).
The population density of this frog population is .

A. 650 frogs
B. 5 frogs per squared kilometer
C. 5 frogs per squared meter
D. 13 frogs per squared meter
E. 130 frogs

Option C.

5 frogs per squared meter.

Explanation:

Population density is the total number of organisms per unit area.

It is calculated as Population ÷ unit area.

The population of the frog = 650

The unit area = 130 square meter.

650÷130= 5.

The answer is 5 frogs per square meter.

Square meter can be used for small space or small area.

try using substitution:

x + y - 6 = x - y. (i'm not giving you the exact answer). since 0 = x - y, then sub 0 in the equation with x - y. combine your like terms, and then use inverse operations, and you'll have your answer.

: -)

if the hares very faster than they are now, and thus the lynx's hunting success rate drops because it will be harder to catch them, the rate that will change will be the pray-rate. the pray-rate will change because more hares will be able to survive, thus more individuals for reproduction, so the end result will be increasing population of hares.

the predator-rate will remain pretty much the same because there will be more than enough pray, but the hunting success rate is stagnant.