You perform a co-transduction experiment with pro+ gal+ arg- man- donor and pro- gal- arg+ man+ recipient. On master plate 1, you select for 1000 pro+ transductants. By screening, you find 400 colonies are gal+, 290 are arg+, and 1000 are man+. On master plate 2, you select for 1000 gal+ transductants. By screening, you find 390 colonies are pro+, 289 are arg+, and 900 are man+. Circle ALL of the following orders which may be possible given the above results. (All or nothing) a. gal---arg---man---pro b. arg---pro---gal---man c. arg--- man---pro---gal d. pro---arg---gal--- man e. pro---gal---man---arg f. pro---gal---arg---man g. None of the above'

arg---pro---gal---man.

Explanation:

The co transduction frequency is directly proportional to the distance between two genes.

The recombination frequency can be calculated as follows;

A - B = (A - B / A ) x 100

Here, A and B represent the different genes.

For plate 1 :

Pro- gal = A - B = (1000 - 400/1000) x 100 = 60% . Here, A is Pro and B is gal.

Pro - Arg = A - C = (1000- 290/1000) x 100 = 71% . Here, C is Arg.

Pro - Man = A - D = (1000-1000/1000) x 100 = 0%. Here D is Man.

For Gal transductants of plate 2

Gal - Pro = A - B = (1000 - 390/1000) x 100 = 61% . Here A is Gal and B is Pro.

Gal - Arg = A - C = (1000- 289/1000) x 100 = 71% .  Here, C is Arg.

Gal - Man = A - D = (1000-900/1000) x 100 = 10%. Here D is Man.

From the recombination frequencies it is clear that the location of genes are in the order of

Thus, the correct answer is option (B).

oceans

indian ocean

pacific ocean

atlantic ocean

arctic ocean

southern ocean