If you observe a selection coefficient of 0.005 against recessive homozygotes, what is the relative fitness of these recessive homozygotes? (please give your answer to three decimal places)

0.995

Explanation:

Given,

The selection coefficient as 0.005

The question pinpoints recessive homozygotes were selected against, the relative fitness

Fitness is in relation to the level of relative survival

The recessive homozygote being selected against, we use W = 1 - s

The formulae of interest

when recessive homozygotes were selected against, the relative fitness

   W   = 1 - s

       = 1- 0.005

       = 0.995 (3 decimal places).

cellular respiration oxidizes food into energy in the form of atps.

glycolysis (6 c hexose) > 2x atps are used > 6c hexose biphosphate > 2 x 3c triphosphate >

2 x 3c pyruvate (2x nadh produced from nad) and (4x atp produced)

pyruvate actively pumped mitochondrial matrix.