The total lung capacity of a typical adult is 5.0 L L . Approximately 20 % % of the air is oxygen. At sea level and at a body temperature of 37 ∘ C ∘C , how many oxygen molecules do the lungs contain at the end of a strong inhalation?

The number of mole of oxygen molecules contained in the lungs at the end of a strong inhalation is 0.04 mole

We'll begin by calculating the number of mole of air in the lungs.

Volume (V) = 5 L

Temperature (T) = 37 °C = 37 + 273 = 310 K

Pressure (P) = 1 atm

Gas constant (R) = 0.0821 atm.L/Kmol

PV = nRT

Divide both side by RT

n = PV / RT

n = (1 × 5) / (0.0821 × 310)

Mole of air = 0.196 mole

Percentage of oxygen = 20% = 0.2

Mole of Oxygen = percent × total mole

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There will be 0.040 mol of oxygen molecules containing at the end of strong inhalation.

Explanation:

Given

volume = 5.0 liter = 5.0 10^-3 m^3,  temperature = 37 degree celsius = 310 K,

Pressure p = 1 atm = 1.013 10^5 Pa.  

By using Boyle's law,

                        PV = nRT

where P represents the pressure,

          V represents the volume,

          R represents the gas constant,

          T represents the temperature

                      n = PV / RT

                         = (1.013 10^5) (5.0 10^-3) / (9.31) (310)

                      n = 0.20 mol

        N oxygen = 0.20 0.20 = 0.040 mol.

for 8 am not sure maybe yes?

for 9 if it is asking if the male is more or less it would be less

hope i even just a little : )

b tumor cells have a cell wall instead of a membrane

explanation:

tumor cells different from normal cells because tumor cells have a cell wall instead of a membrane.