How much thermal energy needs to be added to 0.455 kg of benzene to heat it from 30*c to 50*c

15834 joules is the thermal energy required.

Explanation:

Specific heat capacity of benzene= 1.74 J/gK or 1740 J/Kg K

mass of benzene = 0.455 kg

temperature change= 50-30

                                    =  20 degrees

From the formula:

Specific heat capacity= thermal energy/ (mass)*(temperature change)

thermal energy=  0.455* 1740*20  ( speicfic heat of benzene is converted        

                                                                 to joules per gram)

                              = 15834 joules

what following? you said which of the following. but there is no be more specific.

im back lol i heard you where asking for me