Assuming independent assortment, an individual of genotype ssyyaa would produce gametes of genotypes (in their correct proportions) see section 14.3 (page 297) .

1/8 SYA, 1/8 SYa, 1/8 SyA, 1/8 Sya, 1/8 sYA, 1/8 sYa, 1/8 syA, 1/8 sya

Explanation:

The given genotype is heterozygous for three genes. Considering that all the genes assort independent of each other, the given genotype will form a total of 2^3= 8 types of gametes in equal proportion. During gamete formation, two alleles of a gene (S and s, Y and y, A and a) would separate from each other randomly. This would form a total 8 different types of gametes with the following genotype:

1/8 SYA: 1/8 SYa: 1/8 SyA: 1/8 Sya: 1/8 sYA: 1/8 sYa: 1/8 syA: 1/8 sya

c

explanation:

a

explanation: