Suppose a diploid mosquito is completely heterozygous at all 6 of its chromosomes (2n = 6). how many different combinations of gametes can be produced by this mosquito, assuming no homologous recombination between chromosomes?

8 different combinations of gametes can be produced by this mosquito, assuming no homologous recombination between chromosomes

Explanation:

The mosquito has 6 chromosomes. This means that means it has 3 pairs of homologous chromosomes. Basically, we can assume the number of different gametes by 2 to the power of 3 as their are 3 homologous pairs. This means 2×2×2 which will be equal to the amount of eight. Hence, eight different combination of gametes will be produced.

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