Interpreting data: a baseball is hit straight upat
an ititial velocity of 30 m/s. if the ball has a
negativeacceleration of about 10 m/s 2, how long does the ball take
toreach th top of it's path?

The baseball will 3 second to reach the top of it's path

Explanation:

Initial velocity of the ball= u = 30 m/s

Ball is accelerating against the gravity =

final velocity of the ball when it reaches to  the top path= v = 0

Using first equation of motion:

v = u +at

The baseball will 3 second to reach the top of it's path