If a population with two alleles is at hardy-weinberg equilibrium ad the frequency of one allele is 0.7, what is the heterozygote frequency?
a. 0.7b. 0.42c. 0.3d. 0.21e. insufficient information given to answer the question

B. 0.42

Explanation:

Since the two alleles are at Hardy-Weinberg equilibrium, the sum of the frequency of two alleles will be one. If the frequency of a dominant allele is "p" and that of the recessive allele is "q", then p+q=1

According to the given information, the frequency of one allele in the population is= 0.7

This means that the frequency of the other allele would be= 1-0.7 = 0.3

Frequency of heterozygote in the population =2pq = 2 x 0.7 x 0.3 = 0.42

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