The genetic frequencies of two separate populations are: aa aa aa population 1 .36 .48 .16 population 2 .55 .10 .35 a) what are the genotypic frequencies of the two populations? b) what are the allele frequencies? c) are the populations in hardy-weinberg equilibrium?

Explanation:

first solve for genetic frequency

Population 1

genetic frequency AA = 36/100 = 0.36

                               Aa = 48/100 = 0.48

                               aa = 16/100 = 0.16

Allele frequency

                            A = 0.36 + (0.5 x 0.48) = 0.60

                            a = 0.16 + (0.5 x 0.48) = 0.40

Population 2

genetic frequency AA = 55/100 = 0.55

                               Aa = 10/100 = 0.10

                               aa = 35/100 = 0.35

allele frequency

                            A = 0.55 + (0.5 x 0.10) = 0.60

                            a = 0.35 + (0.5 x 0.10) = 0.40

Weinberg equilibrium states that the allele frequency of a population will remain the same from generation to generation or else there is a catastrophic activity.

from the calculations above, assuming population 1 and 2 are two different generations, it is perfectly in Weinberg equilibrium because the allele frequency is the same.

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white blood cells or wbc s are mainly 2 types-

1.agranulocytes

2.granulocytes

the monocytes or macrophages of agranulocytes , dendritic cells which are accessory leucocytes, and b cells which is one type of lymphocytes   identify the antigens present on the pathogen's surface. these three cells are called antigen presenting cells(apc) which are phagocytes and destroy the antigens by secreting antitoxins. besides this leukocyte is always plays vital role in the immunity of the body.