Suppose the length of maize ears has narrow sense heritability (h2) of 0.70. a population produces ears that have an average length of 29 cm, and from this population a breeder selects a plant producing 35-cm ears to cross by self-fertilization. part apredict the selection differential (s) for this cross. part bpredict the response to selection (r) for this cross.

A is 6cm and B is 2.92

Explanation:

Selection differential is the difference between the population average and the average of the parental population

From this question population average = 29cm

Parental average = 35cm

Thus selection differential (S) = 35 - 29

S= 6

B. Response selection is given by the formula R = h2(S)

Where h2 is the narrow sense heritability and S is selection differential

Thus, R = 0.70 × 6

R = 4.2

the two answers are a, the population of birds with large beaks will increase on the island, and c, the trait for large beaks will be passed on to future generations through natural selection. the reason for that is because if the birds that have beaks developed for eating small seeds lose all of their food, they will go hungry and eventually starve because they physically cannot eat the large seeds, therefore making the population of large beaked birds higher. also, if the trait of large beaks are dominant on the island over small beaks, then over time the large beaked birds will reproduce more and more, while the smaller beaked birds will reproduce less and less because they can't survive with the food provided. that leads to the trait of small beaks disappearing and the trait of large beaks taking over the island.