The p-value corresponding to the chi-square test of independence on alleles is 0.004. if there are a total of 50 snps in the data set, the bonferroni corrected p-value is?

2)what is the goal of association mapping?

3)applying the chi-square test of independence to case and control genotypes at five snps (labeled snp01, snp02, snp03, snp04, snp05), yields the respective p-values 0.05, 0.04, 0.009, 0.004, and 0.10. the genetic phenotype is fructosia.

after bonferroni correction for multiple testing, what snps are declared to be significantly associated with fructosia at the 5% significance level?

4)in what 10-year period did researchers develop technologies for genotyping single nucleotide polymorphisms?

5)what is the chi-square test on independence for genotypes value for the following contingency table?
phenotype a1a1 a1a2 a2a2
case 50 100 50
control 50 100 50
6) in a gwas with 500,000 snps tested among cases and controls, one snp has a chi-square test-statistic p-value of 0.1. after bonferroni correction, is this snp's p-value significant at the 0.05 level?