Cystic fibrosis is a genetic disorder in homozygous recessives that causes death during the teenage years. if 9 in 10,000 newborn babies have the disease,
what are the expected frequencies of the dominant (a1) and recessive (a2) alleles according to the hardy-weinberg equation?
(a) f(a1) = 0.9997, f(a2) = 0.0003(b) f(a1) = 0.9800, f(a2) = 0.0200(c) f(a1) = 0.9700, f(a2) = 0.0300(d) f(a1) = 0.9604, f(a2) = 0.0392

f(A1) = 0.9700, f(A2) = 0.0300

Explanation:

The frequency of homozygous recessive genotype of children is  

As per Hardy weinberg's equation, frequency of homozygous recessive genotype is represented by  

Here

Thus, frequency of recessive allele would be  

as per first law of Hardy weinberg

Hence, option C is correct

when you breathe in, or inhale, your diaphragm contracts (tightens) and moves downward. this increases the space in your chest cavity, into which your lungs expand. the intercostal muscles between your ribs also enlarge the chest cavity. they contract to pull your rib cage both upward and outward when you inhale.