Container that holds 0.152mol of xenon gas has a volume of 3.41l. what will the volume be if an additional 0.190mol of xenon is added to the container and the temperature and pressure are kept constant?

V₂ = 7.7 L

Explanation:

Given data:

Initial moles = 0.152 mol

Initial volume = 3.41 L

Final volume = ?

Final moles = 0.152 + 0.190 = 0.342 mol

Solution:

According to Avogadro law,

V₁/n₁ = V₂/n₂

V₂ = V₁n₂/n₁

V₂ = 3.41 L  × 0.342 mol / 0.152 mol

V₂ = 1.17 L. mol/ 0.152 mol

V₂ = 7.7 L

the answer is trees if i'm not mistaken

the relative atomic mass of an element is the mass of one atom of that element, relative to 1/12th of the mass of a  1212c atom. to convert to an absolute mass in kg, it is necessary to multiply by  1.661×10−271.661×10−27.

the relative atomic mass is roughly equal to the number of neutrons, plus the number of protons, in the nucleus of the atom.

for elements with more than one stable isotope (different types of nucleus with different numbers of neutrons but the same number of protons), the quoted mass is usually the average mass, weighted by the relative abundance of the different isotopes.