In pheasants, there are three plumage variants: light, buff and ring.
the table below gives the results of several crosses between parents of unknown genotype.
use this information to answer questions 8-9 :

parents offspring male x female

1. light x light
2. light x buff
3. buff x light
4. light x ring
5. buff x buff

males all light ½ light, ½ buff ½ light, ½ buff all buff ½ buff, 1/4 light, 1/4 ring all ring
females all light ½ light, ½ buff ½ light, ½ buff all buff ½ buff, 1/4 light, 1/4 ring all ring 6. ring x ring

8. if you were to cross the male parent from family #6 with the female parent from family #3, what offspring ratio would you expect?

a) all buff

b) ½ light, ½ ring

c)% light, ½ buff

d)% buff, ½ ring

e) ½ buff, 1/4 light, 1/4 ring 9.

what is the phenomenon depicted in families 1-6 called?

a) mutation

b) epistasis

c) variable penetrance

d) variable expressivity

e) incomplete dominance