In snapdragons, red flower color (r) is incompletely dominant to white (r), with heterozygous plants being pink. the broad-leaf allele (b) is incompletely dominant over narrow leaves (b), with the heterozygous plants having medium-width leaves. if a red-flowered, broad-leaved plant is crossed with a white-flowered, narrowleaved one, what will be the appearance of the f1 and f2 plants?

-All the F1 individuals will be pink with medium-width leaves.

-The F2 plants can be:

1/16 red flowers, broad leaves

2/16 red flowers, medium-width leaves

1/16 red flowers, narrow leaves

2/16 pink flowers, broad leaves

4/16 pink flowers, medium-width leaves

2/16 pink flowers, narrow leaves

1/16 white flowers, broad leaves

2/16 white flowers, medium-width leaves

1/16 white flowers, narrow leaves

Explanation:

When there is incomplete dominance, the heterozygous genotype produces a phenotype that's intermediate between the homozygous ones.

In the case of flower color:

In the case of leaves width:

A cross between a red-flowered, broad-leaved plant (RRBB) is crossed with a white-flowered, narrowleaved one (rrbb). The homozygous dominant plant only produces RB gametes, and the homozygous recessive plant only produces rb gametes.

-- All the F1 individuals will be heterozygous for both genes (RrBb) and will therefore be pink with medium-width leaves.

The F2 is a result of a F1xF1 cross. Each F1 individual produces the gametes RB, Rb, rB and rb. The possible genotypes and phenotypes arising from the combination of those gametes are:

1/16 RRBB: red flowers, broad leaves

2/16 RRbB: red flowers, medium-width leaves

1/16 RRbb: red flowers, narrow leaves

2/16 rRBB: pink flowers, broad leaves

4/16 rRbB:  pink flowers, medium-width leaves

2/16 rRbb:  pink flowers, narrow leaves

1/16 rrBB: white flowers, broad leaves

2/16 rrbB: white flowers, medium-width leaves

1/16 rrbb: white flowers, narrow leaves

meiosis is the correct answer