Nbined gas law propiems
use the combined gas law to solve the following problems:
1) if i initially have a gas at a pressure of 12 atm, a volume of 23 liters, and a
temperature of 200 k, and then i raise the pressure to 14 atm and
increase the temperature to 300 k, what is the new volume of the gas?
200

V₂ = 29.6 L

Explanation:

According to general gas equation:

P₁V₁/T₁ = P₂V₂/T₂

Given data:

Initial volume = 23 L

Initial pressure = 12 atm

Initial temperature =200 K

Final temperature = 300 K

Final volume = ?

Final pressure = 14 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂  = P₁V₁ T₂/ T₁ P₂  

V₂ = 12 atm × 23 L × 300 K / 200 K × 14 atm  

V₂ = 82800 atm .L. K / 2800 K.atm

V₂ = 29.6 L

she forgot to record a transaction

answer: if she breaths she a thho

explanation: