In the calvin cycle more atp than nadph is used how is this difference made up

Explanation:

The detailed description of photosynthesis is that chlorophyll a becomes oxidized chlorophyll a after being irradiated, and the water in the thylakoid is oxidized by oxidized chlorophyll a to form oxygen and hydrogen ions, and hydrogen ions pass through the class. The ATP synthase on the capsule membrane passes through the membrane into the chloroplast matrix, where it provides a certain chemical potential (ie, an energy produced from a high concentration to a low concentration), and then ADP and Pi on the membrane. Will get energy to form ATP; and NADPH+ is the front chlorophyll a is oxidized by light to release high-energy electrons e, e will be transferred to NADP+ (oxidized coenzyme II), the photolysis of the front water does not produce hydrogen ions? This led to the combination of NADP and H+, which became NADPH.

Next, their use, in front of the photoreaction, in the dark reaction, CO2 will react with the five-carbon compound in the chloroplast matrix, fixed to the formation of a three-carbon compound (one C in CO2, five C in five-carbon compound, Two three-carbon compounds are formed, and then ATP and NADPH supply hydrogen, respectively, and then return to ADP+Pi and NADP+, and the reduced three-carbon compound becomes organic (mostly sugar) and becomes The five-carbon compound will react with CO2 again, which is the Calvin cycle.

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the real answer is b. scintillation counter