Iwill mark as brainliest and 20 points the table shows the solubility of two substances in water at 20 °c.

part 1: what will be the values of l and k for 100 kg of each substance?
part 2: explain your answer for part 1.

answer:

i can't understand the table clearly, so i'm solving it with some assumptions i think is closest to what u wanted to say.

in case of sodium chloride;

mass of water = 100 kg

solubility of nacl = 54 g / 100 g of water

thus the mass of nacl needed for full saturation, l = (54/100) x 100 kg = 54 kg

in case of lead nitrate;

mass of water = 200 kg

mass of pbno₃ = 36 kg

if the solution is fully saturated, solubility of pbno₃ (g per 100 g of water)

k = (36/200) x 100 g   = 18 g

k can be also written as 18 kg per 100 kg of water.

thus the difference in k and l = (54-18) = 36.

answer: wheres the options

explanation:

answer; i believe the correct answer to the above question is ( friction)