Ebony body, held-out wings and sepia eyes are all recessive and all on chromosome 3. the coefficient of coincidence for chromosome 3 is 0.5. a homozygous ebony male is mated to a homozygous held out wing and sepia eyed female. the f1 are wild-type. an f1 female is test crossed to a fly that is homozygous for all three recessive alleles and they produce 1000 progeny. if ebony and held-out are separated by 12 map units, and held-out and sepia are 14 map units apart, and if the order of these loci is ebony, held-out, and sepia: how many ebony, sepia (but not held-out) progeny are expected from this test cross? "