In the absence of recombination, how many genetically different types of gamete can an organism with six homologous chromosome pairs produce?
a) 6
b) 12
c) 36
d) 64
e) none of the above

(D) 64

Explanation:

We have given number of chromosome pair that is haploid number = 6

We have to calculate the number of possible gamete in absence of recombination

The number of garnets is given by where n is haploid number

In question we have given haploid number, that is n=6

So the number of gametes without recombination

So option (d) is the correct answer  

i think the answer is gold im not entirely sure