In the f2 generation of a homozygous round (aa) × homozygous wrinkled (aa) cross in peas, three seeds are chosen at random. what is the probability that two seeds are round and the other is wrinkled?
a) (1/4)^3
b) 3(1/4)(3/4)^2
c) 3(1/4)^2(3/4)
d) (3/4)^3

Option B

Explanation:

First generation cross of homozygous round (AA) × homozygous wrinkled (aa) will give following offspring

Aa, Aa, Aa, Aa

F2 generation of a homozygous round (AA) × homozygous wrinkled (aa) cross in peas will give following offspring

Aa * Aa

AA, Aa, Aa, aa

If we consider that trait of round shaped seed is dominant over wrinkled shaped seed. Then out of four offspring AA, Aa, Aa, aa,

Probability of choosing a wrinkled seed is

Probability of choosing a round  seed is

So the probability that two seeds are round and the other is wrinkled is

Hence, option B is correct