Species a: attcggattattcgagg species b: gtccggttcattggaca species c: atccagatcgttcgtgg which of the following inferences can be made, based on this information?
a. species b and species c most likely diverged from species a since they both have more mutations than species a.
b. species b most likely evolved from species c since they are closest to each other in terms of number of mutations.
c. species a and species c most likely share the most recent common ancestor since they differ by the fewest mutations.
d. species c most likely diverged from species a more recently than species b since species c has fewer mutations than species b.

D. Species C most likely diverged from Species A more recently than Species B since Species C has fewer mutations than Species B.

Explanation: The mutations between species A, B and C can be found counting the differences in the nucleotides (letters). So, the mutations in the sequences between Species A and Species B are 8, between Species A and C are 5 mutations and between Species B and C are 9 mutations. Then, we can proposed that species A and C are more close related because the sequences have fewer mutations and this could happen because they diverged more recently, compared to Species B that have more mutations.

answer; /// i believe the correct answer is (thrombocytopenia); (a)

✿   this landform has a high elevation and a high relief

✿   this landform is a mountain