This problem has been solved! see the answeryou are investigating two traits in fruit flies controlled by one gene each. the b gene controls for body color (black or brown), while the r gene controls for body sculpture (rugose or smooth). after crossing rugose black flies with smooth brown flies, you obtain an f1 generation of 100% smooth black flies. what are the dominant alleles? (1 pt)what are the genotypes of the two parent flies to perform a dihybrid test cross? (1 pt)after running a dihybrid test cross, you find 1000 offspring with the following phenotypes: , rugose406black, smooth86brown, rugose94brown, smooth4141000fill in the expected column with the expected number of offspring in each class of phenotypes. (1 pt)what phenotype classes represent the recombinant offspring? (1 pt each)calculate the relative genetic distance between the body color gene and the body sculpting gene (show your work). (1 pt).
d. The calculated chi-square value is 10.48, and the critical value is 11.35.
The correct option would be option d.
Using the formula for calculating the Chi square ():
For normal eye, normal body;
For normal eyes, ebony body;
For purple eyes, normal body;
For purple eyes, ebony body;
Total = 1.50 + 1.12 + 4.50 + 3.37 = 10.48
Degree of freedom = 4 - 1 = 3
Critical value of = 11.35
Hence, the calculated chi-square value is 10.48, and the critical value is 11.35.
The correct option is d.
i belive it is c
In the first generation, there are 490 brown fruit flies and 4 ebony fruit flies. This mean that the frequency of the brown (p2) is 490/490+4 = 0.992 and the frequency of the ebony (q2) is 4/490+4 = 0.008. The frequency of the dominant allele is p=√0.992=0.995 and the frequency of the recessive allele is q=√0.008=0.089. p+q=1 (HW)
The Hardy-Weinberg equilibrium principle describes that frequency of alleles is unchanged through the generations.
The frequency of alleles is unchanged, population is not evolving.
14.identify the DNA sequence of every human gene.
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for question number for I can say that down syndrome is caused when abnormal cell division results in an extra copy of chromosome 21.
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