The genes for mahogany eyes and ebony body are approximately 25 map units apart on chromosome 3 in drosophila. assume that a mahogany-eyed female was mated to an ebony-bodied male and that the resulting f1 phenotypically wild-type females were mated to mahogany, ebony males to obtain an f2 generation. part a which of the following phenotypes would be expected in the f2 offspring? select all that apply. wild type mahogeny-eyed ebony-bodied mahogeny-eyed, ebony-bodied submitmy answersgive up correctpart b if 1000 f2 offspring are obtained, how many flies of each phenotype are expected? __wild type : __ mahogeny : __ ebony : __ mahogeny, ebony (remember the two genes are 25 mu apart on the same chromosome. in order to determine how many offspring of each type are produced, you must determine if the f1 females carries both mutations on one chromosome, and wildtype alleles on the other or if she carries one mutation and one wildtype allele on each chromosome.) enter your answer as the number of flies of each phenotype separated by a colon.