In cats a form of polydactyly is inherited as an autosomal, complete dominant trait. in key west, florida 16% of the cats have a normal number of digits. what is the frequency of the polydactyly allele in that population? show your work.

p² + 2pq + q² = 1 and p + q = 1

where p and q are the frequencies of the alleles, and p², q² and 2pq are the frequencies of the genotypes.

If 16% of the cats have a normal number of digits (aa), then the frequency of recessive homozygous genotype q² is:

q² = 0.16

⇒ q = √0.16

⇒ q = 0.4

The frequency of recessive allele is 0.4

If the frequency of recessive allele is known, the frequency of dominant (polydactyly) allele p is:

p + q = 1

⇒ p = 1 - q

⇒ p = 1 - 0.4

⇒ p = 0.6

Thus, the frequency of the polydactyly allele in that population is 0.6 or presented in percentage 60%.

thinking it would be fimbriae