Awoman is heterozygous for a rare dominant autosomal genetic disease, neurofibromatosis. she marries a normal man (homozygous recessive for neurofibromatosis), who has red-green color blindness, an x-linked recessive trait. they have children. if the woman is homozygous for normal vision, what is the chance they will have a daughter with color blindness?
a. 100%
b. 50%
c. 0%
d. 25%

Option A

Explanation:

Given -

Man has X-linked recessive trait . Thus its genotype can be represented as

YX'

Woman has normal vision with homozygous genotype i.e "XX"

A cross is carried out between the above two parents thereby producing following offspring -

YX’

XXYXX’

XXYXX’

Out of four offspring two are boy "XY" which do not have Red-Green Color blindness

While the two daughters "XX' " have Red-Green Color blindness

Thus, all the daughters produced have Red-Green Color blindness. Thus the chance of having a daughter with color blindness is 100 percent

Option A

what is this saying?

1. is geographic distribution

2 is increasing complexity

3 is transitional forms