Alright now i only need is number 4 then i’m all done with my science homework
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Biology, 18.11.2019 04:31 leannaadrian
Alright now i only need is number 4 then i’m all done with my science homework
Answers: 1
Biology, 22.06.2019 01:30
Scenario 5 1) take 10 red and 10 black beans and place them, mixed, on the table. record the starting phenotype # and frequencies (% of your total population) of your starting population in the table provided (generation 0). 2) act as a predator. “capture” as many organisms as you can until you have reduced the population to three organisms. put them aside. at this point, the predators die. 3) the remaining organisms each produce 2 clonal offspring. multiply your organisms accordingly and allow them to mix on the table. calculate and record the resultant phenotype # and frequencies (% of your total population) of your population in the table provided (generation 1). 4) repeat the reproduction event, allowing each of your organisms to produce 2 clonal offspring. calculate and record the resultant phenotype # and frequencies (% of your total population) of your population in the table provided (generation 2). 5) repeat the reproduction event, allowing each of your organisms to produce 2 clonal offspring. calculate and record the resultant phenotype # and frequencies (% of your total population) of your population in the table provided (generation 3).
Answers: 1
Biology, 22.06.2019 03:30
Ayoung boy has been found and police are trying to locate his family they take a dna sample from him and begin collec dna samples from families who have missing children if police use dna samples only from the fathers, which type of dn technology can they use to identify the boy's parent? y-chromosome analysis omtdna (mitochondrial dna) analysis vntrs (variable tandem repeats) o pcr (polymerase chain reaction) analysis
Answers: 1
Biology, 22.06.2019 04:00
Asap indicate the coat color and the proportion of offspring with that color for each of the following crosses of rabbits. assume all are homozygous. alleles: a=agouti, c=chinchilla, a=albino, a is dominant over c and a, c is dominant over a agouti x chinchilla a) 1/2 chinchilla, 1/2 agouti b) 3/4 chinchilla, 1/4 agouti c) all agouti
Answers: 1
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