In studying the gene pool of a population, you find that 15% of the population is homozygous recessive (tt) for a trait. how would you use this information to solve for the frequency of the dominant t allele?

square root of 0.15
1–square root of 0.15
15 ÷ 100
0.152

The correct answer would be 1–Square root of 0.15.

It can be solved with the help of Hardy-Weinberg equations; p + q = 1.

Where p indicates the frequency of a dominant allele in a population and q indicates the frequency of the recessive allele in a population.

The percentage of the individual with homozygous recessive genotype is 15%.

Thus, the value of q² = 0.15

So, q = ≈ 0.387

The value of p would be equal to 1 - 0.387 ⇒ 0.613

The answer is 1 - Square root of 0.15

Explanation:

I am 100% positive because I got this question correct on my quiz.

the answer to your question is sperm