Aresearcher was attempting to quantify the amount of ddt () in spinach using gas chromatography mass spectrometry (gcms). first attempts using external calibration proved difficult, as reproducibility and external standard agreement were poor. to overcome these problems, the researcher used the internal standard calibration method with chloroform as the internal standard. to begin, the researcher analyzed a sample containing 6.44 mg/l ddt standard and 1.41 mg/l chloroform as the internal standard, which produced peak areas of 3979 and 9257 for the ddt and chloroform, respectively. a. determine the response factor (f).

Answer

Given data

                   Conc. of standard ddt = 6.44mg/l

                   Conc. of Internal standard chloroform = 1.41mg/l

                   Peak of standard ddt = 3979

                   Peak of internal standard chloroform = 9257

Required

              Response factor (RF) = ?

Solution

               As we know that  

               Response factor (RF) = Peak area/sample amount

So RF for standard ddt

                                  RF = 3979/6.44 = 617.85  (answer)

RF for internal standard chloroform

                                RF = 9257/ 1.41= 6565.24 (answer)

its raceist

explanation:

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each of the 46 original chromosomes splits into two daughter chromosomes, so there are two sets of 46 daughter chromosomes that end up in each cell. human cells have 46 chromosomes. each chromosome consists of a pair of identical chromatids attached together by a structure called a centromere.