Aprobe orbiting venus exerts a gravitational force of 2.58 × 103 n on venus. venus has a mass of 4.87 × 1024 kg. the mass of the probe is 655 kilograms. the gravitational force is 6.67 × 10-11 n*m2/kg2. to three significant digits, the probe is × 106 m from the center of venus.

To solve for the distance between the probe and the center of Venus, use formula:

F = G m1 m2 / r^2

Where:

G is equal to 6.67x10^-11 m3 /kg s2

F = 2.58 x 10^3 N

m1 = 4.87 x 10^24 kg

m2 = 655 kg

Therefore:

F = G m1 m2 / r^2

2.58 x 10^23 = 6.67 x 10^-11 (4.87 x 10^24) (655) / r2
r = 9.08 x 10^6 km

Fg = 2.58 x 10³ N

Mv = 4.87 x 10²⁴ Kg

Md = 655 Kg

So, Fg = G Mv Mp / r²

By putting in the values,

r² = 8.2466 x 10¹³

answer: c. two haploid cells

explanation:

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