Advanced Placement (AP), 14.07.2019 22:30 kayleerose414

Acompany chooses blue and green for its signs and employee uniforms. it decides to write the company name in all capital letters with fancy letters. the company wants to show the new colors and lettering in the annual report. which formatting options would best accomplish this? a. using a theme b. choosing a plain font for the title c. applying conditional formatting d. inserting an image

Answers: 1

Show answers

Answers

Answer from: winnie45

It Would Be Letting Choice B. Choosing A Plain Font For The Title , This Is Because Its blue & Green Shirt

Answer from: letsbestupidcx7734

B. choosing a plain font for the title

Explanation:

Ideally, a company that wants to show new colors and letters in its annual report should do so pleasantly without causing visual discomfort to those who observe the report. In this case, as the company above wishes to use the colors blue and green, it would be more appropriate for it to use a simple font for the title. Thus the report will have a balanced design, called attention to colors and allowing the title to be a complement and not something that fights for attention and provides visual discomfort.

Answer from: Quest

Ibelieve the answer is d.

Answer from: Quest

Answer: the interval on which the curve is concave up is (-∞, -1/2)====== $\displaystyle y = \int_{0}^x \frac{1}{1 + t + t^2} \; dt$ we find the interval where this curve is concave up by finding the interval in which the 2nd derivative is positive.differentiate the curve equation with respect to x $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \end{aligned}$ let the function f denote be the anti-derivative of the inside expression, i.e. a function such that $(d/dx)f(x) = 1/(1 + t + t^2)$ .then use the fundamental theorem of calculus: $\begin{aligned} \frac{dy}{dx} & = \frac{d}{dx} \int_{0}^x \frac{1}{1 + t + t^2} \; dt \\& = \frac{d}{dx} \big[ f(x) - f(0) \big] & & \text{\footnotesize apply ftc} \\ & = \frac{d}{dx}f(x) - 0 \\ & = \frac{1}{x + x + x^2} & & \text{\footnotesize since $\frac{d}{dx}f(x) = \frac{1}{1 + x + x^2}$ } \end{aligned}$ differentiate again to get second derivative. we can use chain rule with 1/x as the outside function and 1 + x + x² as the inside function $\begin{aligned} \frac{d}{dx} \left( \frac{dy}{dx} \right) & = \frac{d}{dx}\left(\frac{1}{1 + x + x^2} \right) \\ \frac{d^2y}{dx^2} & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot \tfrac{d}{dx}(1 + x + x^2) \\ & = \frac{-1}{\left(1 + x + x^2\right)^2} \cdot (1 + 2x) \\ & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \end{aligned}$ find critical numbers of the second derivative. these numbers are where the 2nd deriv. is undefined or zero.where the 2nd derivative is zero: set (d²y/dx²) to equal 0 and solve for x $\begin{aligned} 0 & = \frac{-(1 + 2x)}{\left(1 + x + x^2\right)^2} \\ 0 & = -(1+2x) \\ -1 & = 2x \\ x & = -1/2 \end{aligned}$ where the 2nd derivative is undefined: if the denominator is equal to zero, the derivative will be undefeined. attempting to solve the equation 1 + x + x² = 0results in a discriminant of $b^2 - 4ac = 1^2 - 4(1)(1) = -3$ meaning that the equal 1 + x + x² = 0 has no real solutions and therefore will never equal zero.======our only critical number is x = -1/2.this forms two intervals to test the sign for: (-∞, -1/2) and (-1/2, ∞)test values into the 2nd derivative for (-∞, -1/2)if we try x = -1, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = -1} & = \frac{-(1+2(-1))}{\left(1+(-1)+(-1)^2\right)^2} \\ & = \frac{-(1-2)}{1} \\ & = 1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave up on (-∞, -1/2)test values into the 2nd derivative for (-1/2, ∞)if we try x = 0, we get $\begin{aligned} \left.\frac{d^2y}{dx^2}\right|_{x = 0} & = \frac{-(1+2(0))}{\left(1+(0)+(0)^2\right)^2} \\ & = \frac{-(1)}{1} \\ & = -1 \end{aligned}$ so the since the 2nd derivative of the curve is positive on the interval (-∞, -1/2), the curve is concave down on (-∞, -1/2).the interval on which the curve is concave up is (-∞, -1/2)

Another question on Advanced Placement (AP)

Advanced Placement (AP), 22.06.2019 07:30

Southern tick-associated rash illness (stari) is a disease often carried by deer ticks in the southern united states. which sentence best explains how climate change could increase the number of stari cases? a. infectious diseases may become more widespread as ticks increase their range. b. ticks may weaken the animals they feed on, causing more deaths in the population. c. people who work in agriculture may have to relocate to find new employment. d. rising seas and flooding may result in the displacement of millions of people.

Answers: 1

Answer

Advanced Placement (AP), 27.06.2019 12:00

Which organelle is responsible for the synthesis of enzymes

Answers: 1

Answer

Advanced Placement (AP), 28.06.2019 09:00

What kind of music is the twelve-tone system an example of? a.)whole tone musicb.)numeric musicc.)tonal musicd.)atonal music

Answers: 1

Answer

Advanced Placement (AP), 28.06.2019 14:10

What are the implications for human cooperation as a survival strategy? i need asap