Advanced Placement (AP), 22.06.2021 22:50 babyskitt
The point (1,0) is common to all log functions of the form k(x) = logb x with any base (b). Logarithmic functions share this feature because of a property of exponents that states b0 = 1 for any value of b.
In a log function of the form k(x) = logb x, k(1) = logb 1.
So, by the definition of a logarithm, bk(1) = 1.
Applying the property of exponents to bk(1) = 1 = b0, we get k(1) = 0.
So, (1,0) is a point on the graph.
Answers: 1
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The point (1,0) is common to all log functions of the form k(x) = logb x with any base (b). Logarith...
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