Find the standard deviation of the following R. V. Show all work...no calculator shortcuts...but then check with 1-var stats. X71528
P(X)0.20.49?
Round to FOUR decimal places.

7.6997

Explanation:

Given :

X : 7 15 28

P(X) __0.2 ___0.49 ?

ΣP(x) = 1

0.2 + 0.49 + a = 1

a = 1 - 0.69

a = 0.31

Standard deviation = sqrt(Variance(x))

Variance = Var(X) = Σx²p(x) - E(x)²

E(x) = Σx*p(x) = (7*0.2) + (15*0.49) + (28*0.31) =

E(x) = 17.43

Σx²p(x) = (7^2 * 0.2) + (15^2 * 0.49) + (28^2 * 0.31) = 363.09

Var(X) = Σx²p(x) - E(x)²

Var(X) = 363.09 - 17.43^2

Var(X) = 363.09 - 303.8049

Var(X) = 59.2851

Standard deviation = sqrt(59.2851)

Standard deviation = 7.6996818

= 7.6997

the correct answer is in fact b. spring tides are the highest, while neap tides are the lowest.