Concentrated nitric acid has a molarity of 15.9 M and a density of 1.42 g/mL. Calculate the following concentrations using 1.00 L of HNO3. a) % by mass
b) molality
c) mole fraction

a) percent by mass =

b) molality = 38.01mol/kg

c) mole fraction = 0.40

Explanation:

Given molarity = 15.9 M

moles of = 15.9 moles in 1.00 L of solution

mass of =

Density of solution of = 1.42 g/ml

Volume of solution = 1.00 L = 1000 ml

Mass of solution =

mass of solvent = mass of solution - mass of solute = (1420-1001.7) g = 418.3 g = 0.4183 kg

moles of solvent =

percent by mass =

molality =

mole fraction =

b. as prices rise, quantity demanded goes down.

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