A summer resort rents rowboats to customers but does not allow more than four people to a boat. Each boat is designed to hold no more than 800 pounds. Suppose the distribution of adult males who rent boats, including their clothes and gear, is normal with a mean of 190 pounds and standard deviation of 10 pounds. If the weights of individual passengers are independent, what is the probability that a group of four adult male passengers will exceed the acceptable weight limit of 800 pounds?

.023

Explanation:

190 x 4 = 760

New SD is 10 squared x 4 (people) and sqrt all that down to 20

Draw yourself a normal model. What's the P(the combined weights are at least 800 or above) This is an upper tail test.

So you find your z score (if it weren't normal than a t-score for means).

800-760/20 = 2

On your calc... under 2nd varsnormcdf(2,9^9)

Which gives you .02275 rounded to .023 and that's A for you.

c plumb line

explanation:

because god's plumb line “has a lot to do with the poor. it has a lot to do with righteousness that is living in right relationship with god and neighbor.